1908 United States presidential election in Massachusetts

1908 United States presidential election in Massachusetts

← 1904 November 3, 1908 1912 →
Turnout65.1%[1] Decrease 2.5 pp
 
Nominee William Howard Taft William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate James S. Sherman John W. Kern
Electoral vote 16 0
Popular vote 265,966 155,543
Percentage 58.21% 34.04%

County Results
Taft
  40-50%
  50-60%
  60-70%
  70-80%


President before election

Theodore Roosevelt
Republican

Elected President

William Howard Taft
Republican

The 1908 United States presidential election in Massachusetts took place on November 3, 1908, as part of the 1908 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for president and vice president.

Massachusetts overwhelmingly voted for the Republican nominees, Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan of Nebraska and his running mate John W. Kern of Indiana. Taft won the state by a margin of 24.17%.

Taft was able to win every county in the state of Massachusetts, including a rare Republican victory in Suffolk County, home to the state's capital and largest city, Boston, although Bryan did narrowly win the city of Boston. Bryan had previously lost Suffolk County in 1896 but won it in his rematch with William McKinley in 1900. Bryan had also previously lost Massachusetts to McKinley in both 1896 and 1900, respectively.

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.

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