1836 United States presidential election in Georgia

1836 United States presidential election in Georgia

← 1832 November 7, 1836 1840 →
 
Nominee Hugh White Martin Van Buren
Party Whig Democratic
Alliance State Rights Union Party
Home state Tennessee New York
Running mate John Tyler Richard Johnson
Electoral vote 11 0
Popular vote 24,481 22,778
Percentage 51.80% 48.20%

County Results[1]

The 1836 United States presidential election in Georgia took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Thanks to divisions within the Union party, Georgia voted for State Rights party backed Whig candidate Hugh White over the Union party backed Democratic candidate, Martin Van Buren. White won Georgia by a margin of 3.6%.

This was the only election in which a Democrat won the presidency without carrying Georgia until 1964, nearly 130 years later. Alongside Lyndon Johnson in that year, only Bill Clinton in 1996 (though he carried the state four years prior) and Barack Obama in 2008 and 2012 have been elected without carrying it.[2]

  1. ^ Dubin, Michael J. (2009). United States Presidential Elections, 1788-1860: The Official Results by County and State. McFarland. pp. 43, 62–63. ISBN 9780786454518.
  2. ^ "Historical U.S. Presidential Elections 1789-2020". 270toWin.com. Retrieved December 25, 2021.

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