1840 United States presidential election in Maryland

1840 United States presidential election in Maryland

← 1836 October 30 - December 2, 1840 1844 →

Nominee William Henry Harrison Martin Van Buren Party Whig Democratic Home state Ohio New York Running mate John Tyler none Electoral vote 10 0 Popular vote 33,528 28,752 Percentage 53.83% 46.17%

County Results Harrison   50-60%   60-70% Van Buren   50-60%

President before election Martin Van Buren Democratic Elected President William Henry Harrison Whig

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v t e

The 1840 United States presidential election in Maryland took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.

Maryland voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren, by a margin of 7.66%. As of 2020, this remains the only time in history that an incumbent Democratic president who served a full term has failed to carry any of Maryland's electoral votes in a reelection bid.^[1]

This was the first presidential election that Carroll County was able to vote in.