1868 United States presidential election in Maryland

1868 United States presidential election in Maryland

← 1864 November 3, 1868 1872 →
 
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair, Jr. Schuyler Colfax
Electoral vote 7 0
Popular vote 62,357 30,438
Percentage 67.20% 32.80%

County Results

President before election

Andrew Johnson
Democratic

Elected President

Ulysses S. Grant
Republican

The 1868 United States presidential election in Maryland took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

Maryland voted for the Democratic nominee, Horatio Seymour over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 34.4%.

In this election, Maryland voted 39.72% more Democratic than the nation at-large.[1]

With 67.2% of the popular vote, Maryland would be Seymour's third strongest victory in terms of percentage in the popular vote after Kentucky and Louisiana.[2] To date this is the best performance by a Democrat in Maryland history.

This was the first presidential election that Wicomico County was able to vote in.

  1. ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved April 6, 2023.
  2. ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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