1884 United States presidential election in Maryland

1884 United States presidential election in Maryland

← 1880 November 4, 1884 1888 →
 
Nominee Grover Cleveland James G. Blaine
Party Democratic Republican
Home state New York Maryland
Running mate Thomas A. Hendricks John A. Logan
Electoral vote 8 0
Popular vote 96,866 85,748
Percentage 52.07% 46.10%

County Results

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

The 1884 United States presidential election in Maryland took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president.

Maryland voted for the Democratic nominee, Grover Cleveland, over the Republican nominee, James G. Blaine. by a margin of 5.98%.[1]

In this election, Maryland voted 5.41% more Democratic than the nation at-large.[2]

  1. ^ Humanities, National Endowment for the (November 19, 1884). "Evening capital. (Annapolis, Md.) 1884-1910, November 19, 1884, Image 1". ISSN 2643-8593. Retrieved November 29, 2021.
  2. ^ "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved March 31, 2023.

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