1916 United States presidential election in Missouri

1916 United States presidential election in Missouri

← 1912 November 7, 1916 1920 →
 
Nominee Woodrow Wilson Charles Evans Hughes
Party Democratic Republican
Home state New Jersey New York
Running mate Thomas R. Marshall Charles W. Fairbanks
Electoral vote 18 0
Popular vote 398,032 369,339
Percentage 50.59% 46.94%

County Results

President before election

Woodrow Wilson
Democratic

Elected President

Woodrow Wilson
Democratic

The 1916 United States presidential election in Missouri was held on November 7, 1916 as part of the 1916 United States presidential election. Voters chose 18 representatives, or electors, to the Electoral College, who voted for president and vice president.

Missouri was won by incumbent President, Woodrow Wilson (DNew Jersey), running with Vice President Thomas R. Marshall, with 50.59% of the popular vote, against Supreme Court Justice Charles Evans Hughes (RNew York), running with former vice president Charles W. Fairbanks, with 46.94% of the popular vote.[1] Had Hughes carried the state of Missouri, he would've had 272 electoral votes, enough to win the presidency.

This election was the first in which Missouri more Republican than Kansas since the latter's statehood. This would not recur until 2020.

  1. ^ "1916 Presidential General Election Results – Missouri". Dave Leip's Atlas of U.S. Presidential Elections.

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search