1948 United States presidential election in Missouri

1948 United States presidential election in Missouri
Truman 50-60% 60-70% 70-80% 80-90%	Dewey 50-60% 60-70% 70-80%
President before election; Harry S. Truman; Democratic	Elected President ; Harry S. Truman; Democratic

The 1948 United States presidential election in Missouri took place on November 2, 1948, as part of the 1948 United States presidential election. Voters chose 15^[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Incumbent President Harry S. Truman won his home state of Missouri with 58.11% of the popular vote against Republican Governor of New York Thomas Dewey, who gained 41.49% of the popular vote.^[3]^[4] As of the 2020 presidential election^[update], this is the last election in which Moniteau County and Cole County voted for a Democratic presidential candidate.^[5]^[6]

^ "United States Presidential election of 1948 – Encyclopædia Britannica". Retrieved October 26, 2017.
^ "1948 Election for the Forty-First Term (1949-53)". Retrieved October 26, 2017.
^ "1948 Presidential General Election Results – Missouri". Retrieved October 26, 2017.
^ "The American Presidency Project – Election of 1948". Retrieved October 26, 2017.
^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 239-246 ISBN 0786422173
^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016