1940 United States presidential election in Missouri

1940 United States presidential election in Missouri

← 1936 November 5, 1940[1] 1944 →
 
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York New York
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 15 0
Popular vote 958,476 871,009
Percentage 52.27% 47.50%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1940 United States presidential election in Missouri took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose 15[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Missouri was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 52.27 percent of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 47.50 percent of the popular vote.[3][4]

  1. ^ "United States Presidential election of 1940 — Encyclopædia Britannica". Retrieved August 21, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 21, 2018.
  3. ^ "1940 Presidential General Election Results — Missouri". Retrieved August 21, 2018.
  4. ^ "The American Presidency Project — Election of 1940". Retrieved August 21, 2018.

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