1904 United States presidential election in Wyoming

1904 United States presidential election in Wyoming

← 1900 November 8, 1904 1908 →
 
Nominee Theodore Roosevelt Alton Parker
Party Republican Democratic
Home state New York New York
Running mate Charles W. Fairbanks Henry G. Davis
Electoral vote 3 0
Popular vote 20,846 8,930
Percentage 66.72% 29.08%

County Results
Roosevelt
  50-60%
  60-70%
  70-80%


President before election

Theodore Roosevelt
Republican

Elected President

Theodore Roosevelt
Republican

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The 1904 United States presidential election in Wyoming took place on November 8, 1904, as part of the 1904 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Wyoming was won by the 26th and sitting President of the United States Theodore Roosevelt (RNew York), who assumed office after the Assassination of William McKinley, running with the 26th Vice President of the United States Charles W. Fairbanks. Roosevelt and Fairbanks won with 66.72 percent of the popular vote against Chief Judge of the New York Court of Appeals Alton B. Parker (DNew York), running with Senator Henry G. Davis, with 29.08 percent of the popular vote.[1] Roosevelt won the state by a margin of 37.64%.

  1. ^ "1904 Presidential Election Results Wyoming".

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