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| Elections in Wyoming |
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The 1960 United States presidential election in Wyoming took place on November 8, 1960, as part of the 1960 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
Wyoming was won by the incumbent Vice President, Republican Party (United States) Richard Nixon, running with former United Nations Ambassador Henry Cabot Lodge Jr., with 55.01 percent of the popular vote, against the Democratic nominee, Massachusetts Senator John F. Kennedy, running with Texas Senator Lyndon B. Johnson, with 44.99% of the popular vote, a 10% margin of victory.[3][4] Nixon's victory was significantly smaller than Dwight Eisenhower's 20.2% margin of victory in 1956.
With Nixon's victory in the state, Republicans would see a full sweep of statewide offices that were on the ballot, including the sole House of Representatives election and the Class II Senate seat.
- ^ "United States Presidential election of 1960". Encyclopædia Britannica. Retrieved June 7, 2017.
- ^ "1960 Election for the Forty-Fourth Term (1961-65)". Retrieved June 7, 2017.
- ^ "1960 Presidential General Election Results – Wyoming". Retrieved June 7, 2017.
- ^ "The American Presidency Project – Election of 1960". Retrieved June 7, 2017.
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