1932 United States presidential election in Wyoming

1932 United States presidential election in Wyoming
Roosevelt 40-50% 50-60% 60-70%	Hoover 50-60%
President before election; Herbert Hoover; Republican	Elected President ; Franklin D. Roosevelt; Democratic

The 1932 United States presidential election in Wyoming took place on November 8, 1932, as part of the 1932 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Wyoming was won by the Democratic nominee, the 44th Governor of New York, Franklin D. Roosevelt, running with John Nance Garner, the 39th Speaker of the United States House of Representatives, with 56.07 percent of the popular vote, against the incumbent Republican President Herbert Hoover and Vice President Charles Curtis, with 40.82 percent of the popular vote, a 15.3% margin of victory.^[1] As of the 2020 presidential election^[update], this is the last election in which Johnson County and Crook County have voted for a Democratic presidential candidate, despite the fact that Roosevelt would win statewide by a larger margin 4 years later, in 1936.^[2]

Despite the fact that Hoover had easily carried Wyoming by over 28 points in 1928, Roosevelt easily flipped the state, although his 15.3% margin of victory was slightly less than his national popular vote margin of 17.8%; thus Wyoming voted 2.5% to the right of the nation in this election.

^ "1932 Presidential Election Results – Wyoming".
^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

[Leip-1] "1932 Presidential Election Results – Wyoming".

[how-2] Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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