2000 United States presidential election in Wyoming

2000 United States presidential election in Wyoming

← 1996 November 7, 2000 2004 →
 
Nominee George W. Bush Al Gore
Party Republican Democratic
Home state Texas Tennessee
Running mate Dick Cheney Joe Lieberman
Electoral vote 3 0
Popular vote 147,947 60,481
Percentage 67.76% 27.70%

County results
Bush
  50-60%
  60-70%
  70-80%
  80-90%


President before election

Bill Clinton
Democratic

Elected President

George W. Bush
Republican

The 2000 United States presidential election in Wyoming took place on November 7, 2000, and was part of the 2000 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Wyoming was won by incumbent Texas Governor George W. Bush by a massive 40.06% margin of victory, and his 67.76% of the popular vote made the state his strongest victory in the 2000 election.[1] He was accompanied on the Republican ticket by vice presidential nominee Dick Cheney, formerly a member of the U.S. House of Representatives from Wyoming's at-large district. As of the 2020 presidential election, this is the last time a Republican won Teton County, and thus is also the last time a nominee of any party carried every county in the state, even though subsequent Republican nominees such as Donald Trump have exceeded Bush's share of the overall vote in Wyoming.

  1. ^ "2000 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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