2004 United States presidential election in Wyoming

2004 United States presidential election in Wyoming

← 2000 November 2, 2004 2008 →
Turnout104.7% (of registered voters)
64.1% (of voting age population)
 
Nominee George W. Bush John Kerry
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dick Cheney John Edwards
Electoral vote 3 0
Popular vote 167,629 70,776
Percentage 68.86% 29.07%

County results

President before election

George W. Bush
Republican

Elected President

George W. Bush
Republican

The 2004 United States presidential election in Wyoming took place on November 2, 2004, and was part of the 2004 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.

Wyoming was won by incumbent President George W. Bush by a 39.8% margin of victory. Prior to the election, all 12 news organizations considered this a state Bush would win, or otherwise considered as a safe red state. This was based on pre-election polling, the fact that the last Democrat to win here was Lyndon B. Johnson in 1964, and how Bush carried this state in 2000 with almost 68% of the vote. On election day Bush won every county with over 65% except for Teton County, which Kerry won with 53% and Albany County, which Bush won with 54% of the vote. Bush thus became the first ever Republican to win the White House without carrying Teton County.

With 68.86% of the popular vote, Wyoming would prove to be Bush's second strongest state in the 2004 election after neighboring Utah.[1]

  1. ^ "2004 Presidential Election Statistics". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

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