1879 Iowa Senate election

1879 Iowa Senate election

← 1877 October 14, 1879 1881 →

29 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party Third party
 
Party Republican Democratic Greenback
Last election 38 12 0
Seats after 41 7 2
Seat change Increase3 Decrease5 Increase2

In the 1879 Iowa State Senate elections Iowa voters elected state senators to serve in the eighteenth Iowa General Assembly. Elections were held in 29 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

The general election took place on October 14, 1879.[1]

Following the previous election, Republicans had control of the Iowa Senate with 38 seats to Democrats' 12 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 14 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1879 general election with the balance of power shifting to Republicans holding 41 seats, Democrats having 7 seats, and 2 Greenbackers (a net gain of 3 seats for Republicans and 2 for Greenbackers).

  1. ^ "General Assembly: 18 (01/12/1880 - 01/08/1882)". Iowa Legislature. Retrieved June 28, 2021.

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