1944 Iowa Senate election

1944 Iowa Senate election

← 1942 November 7, 1944 1946 →

30 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 45 5
Seats after 45 5
Seat change Steady Steady

The 1944 Iowa State Senate elections took place as part of the biennial 1944 United States elections. Iowa voters elected state senators in 30 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

The Iowa General Assembly provides statewide maps of each district. To compare the effect of the 1944 redistricting process on the location of each district, contrast the previous map with the map used for 1944 elections.

The primary election on June 5, 1944 determined which candidates appeared on the November 7, 1944 general election ballot.[1][2]

Following the previous election, Republicans had control of the Iowa state Senate with 45 seats to Democrats' 5 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 21 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1944 general election with the balance of power remaining unchanged with Republicans holding 45 seats and Democrats having 5 seats.

  1. ^ "Primary Election 1944 For State Senator" (PDF). Iowa General Assembly. Retrieved June 20, 2020.
  2. ^ "General Election 1944 For State Senator" (PDF). Iowa General Assembly. Retrieved June 20, 2020.

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