1980 United States Senate election in Iowa

1980 United States Senate election in Iowa

← 1974 November 4, 1980 1986 →
 
Nominee Chuck Grassley John Culver
Party Republican Democratic
Popular vote 683,014 581,545
Percentage 53.49% 45.54%

County results
Grassley:      50-60%      60-70%      70-80%
Culver:      50–60%      60–70%

U.S. senator before election

John Culver
Democratic

Elected U.S. Senator

Chuck Grassley
Republican

The 1980 United States Senate election in Iowa was held on November 4, 1980. Incumbent Democratic United States Senator John Culver ran for reelection to a second term, but lost to Republican nominee Chuck Grassley, the United States Congressman from Iowa's 3rd congressional district. This election marked the beginning of eight consecutive victories for Grassley in the Senate. It remains the closest election of his Senate career.[citation needed]


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