2010 Iowa Senate election

Iowa State Senate elections, 2010

← 2008 November 2, 2010 2012 →

25 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Leader Jack Kibbie Paul McKinley
Party Democratic Republican
Leader's seat 4th 36th
Last election 32 18
Seats before 32 18
Seats after 26 24
Seat change Decrease6 Increase6

Results of the elections:
     Republican gain
     Democratic hold      Republican hold
     No election

President of the Senate before election

Jack Kibbie
Democratic

Elected President of the Senate

Jack Kibbie
Democratic

The 2010 Iowa State Senate elections took place as part of the biennial 2010 United States elections. Iowa voters elected state senators in half of the state senate's districts—the 25 odd-numbered state senate districts. State senators serve four-year terms in the Iowa State Senate, with half of the seats up for election each cycle.

The primary election on June 8, 2010 determined which candidates appeared on the November 2, 2010 general election ballot. Primary election results can be obtained here.[1]

Following the previous 2008 Iowa Senate election, Democrats maintained control of the Iowa state Senate with 32 seats.

To reclaim control of the chamber from Democrats, the Republicans needed to net 8 Senate seats.

Democrats maintained control of the Iowa State Senate following the 2010 general election; however, their majority was significantly reduced from 32 to 26 seats. Republicans saw their numbers soar from 18 to 24 seats.

  1. ^ "Primary Election 2010 Canvass Summary" (PDF). Iowa Secretary of State. Retrieved April 1, 2020.

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