1936 United States presidential election in Iowa

1936 United States presidential election in Iowa

← 1932 November 3, 1936[1] 1940 →

All 11 Iowa votes to the Electoral College
 
Nominee Franklin D. Roosevelt Alf Landon
Party Democratic Republican
Home state New York Kansas
Running mate John Nance Garner Frank Knox
Electoral vote 11 0
Popular vote 621,756 487,977
Percentage 54.41% 42.70%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

The 1936 United States presidential election in Iowa took place on November 3, 1936, as part of the 1936 United States presidential election. Iowa voters chose 11[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Iowa was won by incumbent President Franklin D. Roosevelt (DNew York), running with Vice President John Nance Garner, with 54.41% of the popular vote, against Governor Alf Landon (RKansas), running with Frank Knox, with 42.70% of the popular vote.[3][4] As of the 2020 presidential election, this is the last occasion when Sioux County, Lyon County and O'Brien County have voted for a Democratic presidential candidate.[5][6] Iowa would not vote Democratic in a presidential election again until 1948.

  1. ^ "United States Presidential election of 1936 - Encyclopædia Britannica". Retrieved December 31, 2018.
  2. ^ "1936 Election for the Thirty-eighth Term (1937-41)". Retrieved December 31, 2018.
  3. ^ "1936 Presidential General Election Results - Iowa". Retrieved December 31, 2018.
  4. ^ "The American Presidency Project - Election of 1936". Retrieved December 31, 2018.
  5. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 196-199 ISBN 0786422173
  6. ^ Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search