1936 Iowa Senate election

1936 Iowa Senate election

← 1934 November 3, 1936 1938 →

32 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 22 28
Seats before 24[a] 26[a]
Seats after 28 22
Seat change Increase4 Decrease4

The 1936 Iowa State Senate elections took place as part of the biennial 1936 United States elections. Iowa voters elected state senators in 32 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the 1936 elections is provided by the Iowa General Assembly here.

The primary election on June 1, 1936 determined which candidates appeared on the November 3, 1936 general election ballot.[1][2]

Following the previous election, Democrats had control of the Iowa state Senate with 28 seats to Republicans' 22 seats. Due to some vacancies and special elections, by election day 1936, Democrats held 26 seats to Republicans' 24.[a]

To claim control of the chamber from Democrats, the Republicans needed to net 2 Senate seats.

Republicans gained control of the Iowa State Senate following the 1936 general election with the balance of power shifting to Republicans holding 28 seats and Democrats having 22 seats (a net gain of 4 seats for Republicans).


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  1. ^ "Primary Election 1936 For State Senator" (PDF). Iowa General Assembly. Retrieved June 24, 2020.
  2. ^ "General Election 1936 For State Senator" (PDF). Iowa General Assembly. Retrieved June 24, 2020.

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