1893 Iowa Senate election

1893 Iowa Senate election

← 1891 November 7, 1893 1895 →

24 out of 50 seats in the Iowa State Senate
26 seats needed for a majority
  Majority party Minority party Third party
 
Party Republican Democratic Populist
Last election 24 25 1
Seats after 34 16 0
Seat change Increase10 Decrease9 Decrease1

In the 1893 Iowa State Senate elections Iowa voters elected state senators to serve in the twenty-fifth Iowa General Assembly. Elections were held in 24 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate.

A statewide map of the 50 state Senate districts in the 1893 elections is provided by the Iowa General Assembly here.

The general election took place on November 7, 1893.[1]

Following the previous election, Democrats had control of the Iowa Senate with 25 seats to Republicans' 24 seats and one seat held by the People's Party.

To claim control of the chamber from Democrats, the Republicans needed to net 2 Senate seats.

Republicans claimed control of the Iowa State Senate following the 1893 general election with the balance of power shifting to Republicans holding 34 seats, Democrats having 16 seats, and the People's Party losing its lone seat (a net gain of 10 seats for Republicans).

  1. ^ "The Twenty-Fifth General Assembly. SENATE" (PDF). Iowa Official Register. Retrieved June 25, 2021.

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search