1916 Iowa Senate election

1916 Iowa Senate election

← 1914 November 7, 1916 1918 →

30 out of 50 seats in the Iowa Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 35 15
Seats after 40 10
Seat change Increase5 Decrease5

Results
     Democratic gain      Republican gain
     Democratic hold      Republican hold

The 1916 Iowa Senate elections took place as part of the biennial 1916 United States elections. Iowa voters elected state senators in 30 of the senate's 50 districts. State senators serve four-year terms in the Iowa Senate.

A statewide map of the 50 state Senate districts in the 1916 elections is provided by the Iowa General Assembly here.

The primary election on June 5, 1916, determined which candidates appeared on the November 7, 1916 general election ballot.[1][2]

Following the previous election, Republicans had control of the Iowa Senate with 35 seats to Democrats' 15 seats.

To claim control of the chamber from Republicans, the Democrats needed to net 11 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1916 general election with the balance of power shifting to Republicans holding 40 seats and Democrats having 10 seats (a net gain of 5 seats for Republicans).

  1. ^ "Primary Election 1916 For State Senator" (PDF). Iowa General Assembly. Retrieved June 14, 2021.
  2. ^ "General Election 1916 For State Senator" (PDF). Iowa General Assembly. Retrieved June 14, 2021.

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