1916 United States presidential election in Iowa

1916 United States presidential election in Iowa

← 1912 November 7, 1916 1920 →
 
Nominee Charles Evans Hughes Woodrow Wilson
Party Republican Democratic
Home state New York New Jersey
Running mate Charles W. Fairbanks Thomas R. Marshall
Electoral vote 13 0
Popular vote 280,439 221,699
Percentage 54.25% 42.89%

County Results

President before election

Woodrow Wilson
Democratic

Elected President

Woodrow Wilson
Democratic

The 1916 United States presidential election in Iowa took place on November 7, 1916, as part of the 1916 United States presidential election which was held throughout all contemporary 48 states. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.

Iowa was won by Republican nominee, U.S. Supreme Court Justice Charles Evans Hughes of New York, and his running mate Senator Charles W. Fairbanks of Indiana. They defeated Democratic nominees, incumbent Democratic President Woodrow Wilson and Vice President Thomas R. Marshall.

Hughes won the state by a margin of 11.36%.

With 54.25% of the vote, Iowa would prove to be Hughes' fourth strongest state in terms of popular votes percentage after Vermont, New Jersey and Pennsylvania.[1]

This election was won of only three elections in the state’s history that it voted against the winning incumbent as Woodrow Wilson was the first presidential incumbent to secure a second consecutive term in office without carrying the state until FDR in 1940 who lost it in his third and then fourth presidential victory in 1944. They are currently the only Presidents in history to have carried the state upon winning the White House and lost it upon winning re-election.

  1. ^ "1916 Presidential Election Statistics". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

© MMXXIII Rich X Search. We shall prevail. All rights reserved. Rich X Search