1928 Iowa Senate election

1928 Iowa Senate election

← 1926 November 6, 1928 1930 →

31 out of 50 seats in the Iowa Senate
26 seats needed for a majority
  Majority party Minority party
 
Party Republican Democratic
Last election 49 1
Seats before 48[a] 2[a]
Seats after 48 2
Seat change Steady Steady

The 1928 Iowa Senate elections took place as part of the biennial 1928 United States elections. Iowa voters elected state senators in 31 of the senate's 50 districts. State senators serve four-year terms in the Iowa Senate.

A statewide map of the 50 state Senate districts in the 1928 elections is provided by the Iowa General Assembly here.

The primary election on June 4, 1928 determined which candidates appeared on the November 6, 1928 general election ballot.[1][2]

Following the previous election, Republicans had control of the Iowa Senate with 49 seats to Democrats' 1 seat. A special election in district 20 in 1927 saw the seat flip from Republican to Democratic control.

To claim control of the chamber from Republicans, the Democrats needed to net 24 Senate seats.

Republicans maintained control of the Iowa State Senate following the 1928 general election with the balance of power remaining unchanged with Republicans holding 48 seats and Democrats having 2 seats.


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  1. ^ "Primary Election 1928 For State Senator" (PDF). Iowa General Assembly. Retrieved January 16, 2021.
  2. ^ "Primary Election 1928 For State Senator" (PDF). Iowa General Assembly. Retrieved January 16, 2021.

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